How to Initialize String Variables

Initializing String Variables 

#include <stdio.h> int main() { int i; char strl[] = "Hello world"; char str3[12] = "Hello world"; char str2[5]; str2[0]='M'; str2[1]='E'; str2[2]='3'; str2[3]='0'; str2[4]='\0'; printf("str1==%s\n",str1);  -------------> for(i=0; i<5; i++) { printf("str2[%d]==%c\n", i, str2[i]); -----> } return 0; } OUTPUT str1==Hello world str2[0]==M str2[1]==E str2[2]==3 str2[3]==0 str2[4]==	Declare as an array of type char Can initialize implicitly or explicitly (using a string constant or using individual characters and a terminating NULL character)
	Can print an entire string using printf and %s format specification Can print individual elements of a suing by indexing and using %c format specification

Strings - Practice 1 

Declare: 

A string variable named me30 and and initialize it to hold the string, “ME 30 rocks!”

Determine: 

The minimum number of characters of array elements needed to store the string: 

length of the string 

What is stored in me30[2]? 

What is stored in me30[12]?

Solution 

Declare: 

char me30[]="ME 30 rocks!" //

The minimum number of character array elements need to store is given here. 

13 

Try sizeof(me30)/sizeof(char) (Or) 

strlen(me30)+ 1 

me30[2]== space // Space is stored in me30[2]

What is stored in me30[12]=='\0'  //Null character is stored in me30[12].